Mercurial > octave-nkf
comparison src/DLD-FUNCTIONS/qz.cc @ 9758:09da0bd91412
Periodic grammar check of Octave documentation files to ensure common format
Use double spaces after a period at start of new sentence
Do not use @iftex blocks where @tex block is sufficient
author | Rik <rdrider0-list@yahoo.com> |
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date | Fri, 23 Oct 2009 09:28:14 -0700 |
parents | 923c7cb7f13f |
children | 2c279308f6ab |
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9757:95ad9c2a27e2 | 9758:09da0bd91412 |
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211 @var{QZ} decomposition. There are three ways to call this function:\n\ | 211 @var{QZ} decomposition. There are three ways to call this function:\n\ |
212 @enumerate\n\ | 212 @enumerate\n\ |
213 @item @code{lambda = qz(A,B)}\n\ | 213 @item @code{lambda = qz(A,B)}\n\ |
214 \n\ | 214 \n\ |
215 Computes the generalized eigenvalues\n\ | 215 Computes the generalized eigenvalues\n\ |
216 @iftex\n\ | |
217 @tex\n\ | 216 @tex\n\ |
218 $\\lambda$\n\ | 217 $\\lambda$\n\ |
219 @end tex\n\ | 218 @end tex\n\ |
220 @end iftex\n\ | |
221 @ifnottex\n\ | 219 @ifnottex\n\ |
222 @var{lambda}\n\ | 220 @var{lambda}\n\ |
223 @end ifnottex\n\ | 221 @end ifnottex\n\ |
224 of @math{(A - s B)}.\n\ | 222 of @math{(A - s B)}.\n\ |
225 @item @code{[AA, BB, Q, Z, V, W, lambda] = qz (A, B)}\n\ | 223 @item @code{[AA, BB, Q, Z, V, W, lambda] = qz (A, B)}\n\ |
226 \n\ | 224 \n\ |
227 Computes qz decomposition, generalized eigenvectors, and \n\ | 225 Computes qz decomposition, generalized eigenvectors, and \n\ |
228 generalized eigenvalues of @math{(A - sB)}\n\ | 226 generalized eigenvalues of @math{(A - sB)}\n\ |
229 @iftex\n\ | |
230 @tex\n\ | 227 @tex\n\ |
231 $$ AV = BV{ \\rm diag }(\\lambda) $$\n\ | 228 $$ AV = BV{ \\rm diag }(\\lambda) $$\n\ |
232 $$ W^T A = { \\rm diag }(\\lambda)W^T B $$\n\ | 229 $$ W^T A = { \\rm diag }(\\lambda)W^T B $$\n\ |
233 $$ AA = Q^T AZ, BB = Q^T BZ $$\n\ | 230 $$ AA = Q^T AZ, BB = Q^T BZ $$\n\ |
234 @end tex\n\ | 231 @end tex\n\ |
235 @end iftex\n\ | |
236 @ifnottex\n\ | 232 @ifnottex\n\ |
237 @example\n\ | 233 @example\n\ |
238 @group\n\ | 234 @group\n\ |
239 \n\ | 235 \n\ |
240 A*V = B*V*diag(lambda)\n\ | 236 A*V = B*V*diag(lambda)\n\ |