view scripts/strings/dec2base.m @ 11523:fd0a3ac60b0e

update copyright notices
author John W. Eaton <jwe@octave.org>
date Fri, 14 Jan 2011 05:47:45 -0500
parents c776f063fefe
children c792872f8942
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## Copyright (C) 2000-2011 Daniel Calvelo
##
## This file is part of Octave.
##
## Octave is free software; you can redistribute it and/or modify it
## under the terms of the GNU General Public License as published by
## the Free Software Foundation; either version 3 of the License, or (at
## your option) any later version.
##
## Octave is distributed in the hope that it will be useful, but
## WITHOUT ANY WARRANTY; without even the implied warranty of
## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
## General Public License for more details.
##
## You should have received a copy of the GNU General Public License
## along with Octave; see the file COPYING.  If not, see
## <http://www.gnu.org/licenses/>.

## -*- texinfo -*-
## @deftypefn  {Function File} {} dec2base (@var{d}, @var{base})
## @deftypefnx {Function File} {} dec2base (@var{d}, @var{base}, @var{len})
## Return a string of symbols in base @var{base} corresponding to
## the non-negative integer @var{d}.
##
## @example
## @group
## dec2base (123, 3)
##      @result{} "11120"
## @end group
## @end example
##
## If @var{d} is a vector, return a string matrix with one row per value,
## padded with leading zeros to the width of the largest value.
##
## If @var{base} is a string then the characters of @var{base} are used as
## the symbols for the digits of @var{d}.  Space (' ') may not be used
## as a symbol.
##
## @example
## @group
## dec2base (123, "aei")
##      @result{} "eeeia"
## @end group
## @end example
##
## The optional third argument, @var{len}, specifies the minimum
## number of digits in the result.
## @seealso{base2dec, dec2bin, dec2hex}
## @end deftypefn

## Author: Daniel Calvelo <dcalvelo@yahoo.com>
## Adapted-by: Paul Kienzle <pkienzle@kienzle.powernet.co.uk>

function retval = dec2base (d, base, len)

  if (nargin < 2 || nargin > 3)
    print_usage ();
  endif

  # Create column vector for algorithm
  if (columns (d) > 1 || !isvector (d))
    d = d(:);
  endif

  if (any (d < 0 | d != fix (d)))
    error ("dec2base: input must be non-negative integers");
  endif

  symbols = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  if (ischar (base))
    symbols = base;
    base = length (symbols);
    if (length (unique (symbols)) != base)
      error ("dec2base: symbols representing digits must be unique");
    endif
    if (any (isspace (symbols)))
      error ("dec2base: whitespace characters are not valid symbols");
    endif
  elseif (! isscalar (base))
    error ("dec2base: cannot convert from several bases at once");
  elseif (base < 2 || base > length (symbols))
    error ("dec2base: BASE must be between 2 and 36, or a string of symbols");
  endif
  
  ## determine number of digits required to handle all numbers, can overflow
  ## by 1 digit
  max_len = round (log (max (max (d), 1)) ./ log (base)) + 1;

  if (nargin == 3)
    max_len = max (max_len, len);
  endif
  
  ## determine digits for each number
  digits = zeros (length (d), max_len);
  for k = max_len:-1:1
    digits(:,k) = mod(d, base);
    d = round ((d - digits(:,k)) / base);
  endfor

  ## convert digits to symbols
  retval = reshape (symbols (digits+1), size (digits));

  ## Check if the first element is the zero symbol. It seems possible
  ## that LEN is provided, and is less than the computed MAX_LEN and
  ## MAX_LEN is computed to be one larger than necessary, so we would
  ## have a leading zero to remove.  But if LEN >= MAX_LEN, we should
  ## not remove any leading zeros.
  if ((nargin == 2 || (nargin == 3 && max_len > len))
      && all (retval(:,1) == symbols(1)) && length (retval) != 1)
    retval = retval(:,2:end);
  endif

endfunction

%!test
%! s0='';
%! for n=1:13
%!   for b=2:16
%!     pp=dec2base(b^n+1,b);
%!     assert(dec2base(b^n,b),['1',s0,'0']);
%!     assert(dec2base(b^n+1,b),['1',s0,'1']);
%!   end
%!   s0=[s0,'0'];
%! end

%!test
%! digits='0123456789ABCDEF';
%! for n=1:13
%!   for b=2:16
%!     pm=dec2base(b^n-1,b);
%!     assert(length(pm),n);
%!     assert(all(pm==digits(b)));
%!   end
%! end

%!test
%! for b=2:16
%!   assert(dec2base(0,b),'0');
%! end

%!assert(dec2base(0,2,4), "0000");
%!assert(dec2base(2^51-1,2), ...
%!       '111111111111111111111111111111111111111111111111111');
%!assert(dec2base(uint64(2)^63-1,16), '7FFFFFFFFFFFFFFF');

%%Test input validation
%!error dec2base ()
%!error dec2base (1)
%!error dec2base (1, 2, 3, 4)
%!error dec2base (-1)
%!error dec2base (1.1)
%!error dec2base (1,"ABA")
%!error dec2base (1,"A B")
%!error dec2base (1, ones(2))
%!error dec2base (1, 1)
%!error dec2base (1, 37)