view scripts/special-matrix/magic.m @ 25235:27e6b38571d3

magic.m: Issue an error if input N is negative (bug #53441). * magic.m: Check for negative N and call error() if found. Add BIST test to check new code.
author Dildar Sk <dildarsk101010@gmail.com>
date Fri, 23 Mar 2018 19:03:45 -0400
parents 6652d3823428
children 00f796120a6d
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## Copyright (C) 1999-2018 Paul Kienzle
##
## This file is part of Octave.
##
## Octave is free software: you can redistribute it and/or modify it
## under the terms of the GNU General Public License as published by
## the Free Software Foundation, either version 3 of the License, or
## (at your option) any later version.
##
## Octave is distributed in the hope that it will be useful, but
## WITHOUT ANY WARRANTY; without even the implied warranty of
## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
## GNU General Public License for more details.
##
## You should have received a copy of the GNU General Public License
## along with Octave; see the file COPYING.  If not, see
## <https://www.gnu.org/licenses/>.

## -*- texinfo -*-
## @deftypefn {} {} magic (@var{n})
##
## Create an @var{n}-by-@var{n} magic square.
##
## A magic square is an arrangement of the integers @code{1:n^2} such that the
## row sums, column sums, and diagonal sums are all equal to the same value.
##
## Note: @var{n} must be a scalar greater than or equal to 3.  If you supply
## @var{n} less than 3, magic returns either a nonmagic square, or else the
## degenerate magic squares 1 and [].
## @end deftypefn

function A = magic (n)

  if (nargin != 1)
    print_usage ();
  endif

  n = fix (n);
  if (n < 0)
    error ("magic: N must be non-negative");
  elseif (n < 1)
    A = [];
  elseif (mod (n, 2) == 1)

    shift = floor ((0:n*n-1)/n);
    c = mod ([1:n*n] - shift + (n-3)/2, n);
    r = mod ([n*n:-1:1] + 2*shift, n);
    A(c*n+r+1) = 1:n*n;
    A = reshape (A, n, n);

  elseif (mod (n, 4) == 0)

    A = reshape (1:n*n, n, n)';
    I = [1:4:n, 4:4:n];
    J = fliplr (I);
    A(I,I) = A(J,J);
    I = [2:4:n, 3:4:n];
    J = fliplr (I);
    A(I,I) = A(J,J);

  elseif (mod (n, 4) == 2)

    m = n/2;
    A = magic (m);
    A = [A, A+2*m*m; A+3*m*m, A+m*m];
    k = (m-1)/2;
    if (k > 1)
      I = 1:m;
      J = [2:k, n-k+2:n];
      A([I,I+m],J) = A([I+m,I],J);
    endif
    I = [1:k, k+2:m];
    A([I,I+m],1) = A([I+m,I],1);
    I = k + 1;
    A([I,I+m],I) = A([I+m,I],I);

  endif

endfunction


%!test
%! for i = 3:30
%!   A = magic (i);
%!   assert (norm(diff([sum(diag(A)),sum(diag(flipud(A))),sum(A),sum(A')])),0);
%! endfor

## Not a magic square but we must return something (bug #46672).
## While one day we may change the actual return of magic (2),
## this properties still must be true.
%!test <*46672>
%! m = magic (2);
%! assert (size (m), [2 2]);
%! assert (m, [4 3; 1 2]);

%!assert (isempty (magic (0)))
%!assert (magic (1), 1)
%!assert (magic (1.5), 1)

## Test input validation
%!error magic ()
%!error magic (1, 2)
%!error <N must be non-negative> magic (-5)