view apps/free_license/urls.py @ 213:6f285552a9d0 default tip

Remove requirement to be logged in to see comments
author Jordi Gutiérrez Hermoso <jordigh@octave.org>
date Thu, 16 Jan 2014 10:59:05 -0500
parents c7be7def8b57
children
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from django.conf.urls.defaults import *

urlpatterns = patterns('apps.free_license.views',
    url(r'^$', 'index', name='license_info'),
    (r'^(?P<license_name>\w*)/$', 'show_license'),
)